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def knapsack_with_mandatory(capacity, file_sizes, mandatory_index): n = len(file_sizes) mandatory_size = file_sizes[mandatory_index] # Convert all sizes to integers (bytes) to avoid floating point issues capacity = int(capacity * 1000) # Convert MB to KB file_sizes = [int(size * 1000) for size in file_sizes] # Convert MB to KB mandatory_size = file_sizes[mandatory_index] # Reduce capacity by the size of the mandatory file remaining_capacity = capacity - mandatory_size # Create a new list without the mandatory file remaining_files = file_sizes[:mandatory_index] + file_sizes[mandatory_index+1:] dp = [[0 for _ in range(remaining_capacity + 1)] for _ in range(n)] for i in range(1, n): for w in range(1, remaining_capacity + 1): if remaining_files[i-1] <= w: dp[i][w] = max(remaining_files[i-1] + dp[i-1][w-remaining_files[i-1]], dp[i-1][w]) else: dp[i][w] = dp[i-1][w] # Backtrack to find which files were included w = remaining_capacity included_files = [mandatory_index] # Start with the mandatory file for i in range(n-1, 0, -1): if dp[i][w] != dp[i-1][w]: if i >= mandatory_index: included_files.append(i+1) else: included_files.append(i) w -= remaining_files[i-1] return (dp[n-1][remaining_capacity] + mandatory_size) / 1000, included_files[::-1] # Convert KB back to MB # File sizes in MB file_sizes = [33.7, 16.2, 1.5, 1.0, 1.8, 2.7, .9, 6.6, 5.2, 2.0, 1.8, 1.1, 5.1, 6.4, 7.3] capacity = 20 # Hard drive capacity in MB mandatory_file = 14 # Index of file 15 (remember, Python uses 0-based indexing) total_size, selected_files = knapsack_with_mandatory(capacity, file_sizes, mandatory_file) print(f"Maximum total size: {total_size:.1f} MB") print("Selected files:") for i in selected_files: print(f"File {i+1}: {file_sizes[i]} MB") print(f"Total size of selected files: {sum([file_sizes[i] for i in selected_files]):.1f} MB") print(f"Unused space: {capacity - sum([file_sizes[i] for i in selected_files]):.1f} MB")
Hint: Remember to include output statements in your code, such as print, console.log, printf, fmt.Println() or System.out.println.

Benefits of TheCodeground Online IDE

Multi-Language Support

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Experience fast and efficient code execution with immediate feedback in the integrated terminal. This feature helps streamline the development process, allowing developers to quickly test and debug their code.

Free to Use

Enjoy the full range of features at no cost. TheCodeground Online IDE is completely free, providing a valuable resource for developers without any subscription fees. This makes it an ideal choice for students, hobbyists, and professionals alike.

Cloud-Based Platform

As a cloud-based IDE, TheCodeground allows you to access your projects from anywhere, at any time. This flexibility ensures that you can continue coding without being tied to a specific device or location.

Customizable Environment

Tailor the IDE to your preferences with customizable themes, layouts, and extensions. This personalization ensures a comfortable and productive coding environment.

Why Choose TheCodeground Over Other Online IDEs?

TheCodeground Online IDE stands out from the competition with its comprehensive feature set, ease of use, and cost-effectiveness. Unlike many other online IDEs that require subscriptions or offer limited free plans, TheCodeground provides all its features for free. Our multi-language support, real-time collaboration, and advanced debugging tools ensure that you have everything you need for effective development. Additionally, our user-friendly interface and customizable environment make coding a pleasant experience, regardless of your expertise level. Choose TheCodeground Online IDE for a seamless, efficient, and enjoyable coding experience.

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